Yes it is. 3 is the amplitude
Answer - 13.098 gm
Description -
Dear student,
As we know 
⇒ Mass = Density * Volume
so multiplying given Volume with the Density of gold ,we can calculate the mass of the gold . Density of gold at room temp. is 19.32 grams per cubic centimeter.
so mass of the sliver of gold = 19.32 * 0.678 = 13.098 (ans)
X - 6 is th algebraic expession for six lss than a number. x represents the number and you are taking 6 away from it. This is the basis of all algebra
Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580
Answer:
385 cards
Step-by-step explanation:
First, find 40% and 25% of 1100.
2/5 * 1100
2200/5 = 440 cards dated before 1970
1/4 * 1100
1100/4 = 275 cards dated between 1970 and 2000
Then add the two amounts together.
440 + 275 = 715 cards between pre-1970 and 2000
After that, subtract your new sum from 1100.
1100 - 715 = 385 cards after 2000
(Or to make it easier, just find 35% of 1100.)
