The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
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According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:
y = -x + 6.
<h3>What is the equation of the circle?</h3>
The equation of a circle of center 
and radius r is given by:
In this problem, we have that the center is at point (0,2), hence:
It goes through point (3,3), hence:
Hence, the equation is:
<h3>What is the equation of the tangent line at point W?</h3>
It is given by:
Applying implicit differentiation, we have that:
Point W(3,3), hence:
Hence the equation is:
y - 3 = -(x - 3).
y = -x + 6.
More can be learned about the equation of a tangent line at brainly.com/question/8174665
Answer:
48
Step-by-step explanation:
Area of a square = length of side squared
square root of 144 is 12
four equal sides in a square
12 * 4 = 48
