Answer: the number of adult tickets is 210
The number if student tickets is 270
Step-by-step explanation:
Let x represent the number of adult tickets that were purchased.
Let y represent the number of student tickets that were purchased.
At the ritz, concert tickets for adults cost $6 and tickets for students cost $4. If the cost of total tickets purchased is $2340, then,
6x + 4y = 2340 - - - - - - - -1
Total number of tickets purchased is 480. This means that
x + y = 480
x = 480 - y
Substituting x = 480 - y into equation 1, it becomes
6(480 - y) + 4y = 2340
2880 - 6y + 4y = 2340
- 6y + 4y = 2340 - 2880
-2y = - 540
y = - 540/-2 = 270
x = 480 - 270
x = 210
Answer:
so basically first add 700+300 which would come up to 1000. 300+100 is 400 so add 100 to the 1000 and you have 1100
Answer:
Step-by-step explanation:
the whole bag is made of 5 orange +4blue+3 green= 12 marbles
P of orange than green = P orange * P green = 5/12 * 3/12 = 15/144 = 5/48
you multiply when the events depend on each other to happen, so for the orange and then green to happen you need the orange and also the green
Answer:
The number of sweets in the 10th bag is 53
Step-by-step explanation:
Given
Let the Number of sweets in a bag be represented by x and frequency be represented by f
The table is as follows
x F
39 1
40 2
41 5
42 0
43 1
Mean = 42
Required
How many sweets are in the 10th bag?
Represent the number of sweets in the 10th bag by y;
The table becomes
x F
39 1
40 2
41 5
42 0
43 1
y 1
The mean of observation is calculated using the following formula;
Mean = ∑fx/∑f
Where ∑ means summation
fx means f * x; i.e. product of frequency and number of sweets
f represents frequency;
Calculating ∑fx
∑fx = 39 * 1 + 40 * 2 + 41 * 5 + 42 * 0 + 43 * 1 + y * 1
∑fx = 39 + 80+ 205 + 0 + 43 + y
∑fx = 367 + y
Calcuating ∑f
∑f = 1 + 2 + 5 + 0 + 1 + 1
∑f = 10
Recall that
Mean = ∑fx/∑f and Mean = 42;
So, Mean = ∑fx/∑f becomes

Multiply both sides by 10


Subtract 367 from both sides



Hence, the number of sweets in the 10th bag is 53
Answer:
B. 64
......there are nine nolumbers in every interval . ..