Answer:


Step-by-step explanation:
Given


Solving (a); Point estimate of mean
To do this, we simply calculate the sample mean




Solving (b); Point estimate of standard deviation
To do this, we simply calculate the sample standard deviation





<em>Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.</em>
<em>Hence, the need to solve for sample mean and sample standard deviation</em>
The equation of function g(x) in terms of f(x) is g(x) = -3[f(x)].
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given:
genera form of an exponential function is y=aeᵇˣ
Now, equation for f(x) is
f(x) = 
Similarly, graph for g(x) is
g(x) = 
Comparing the two function a relation can be establish
g(x) = -3[f(x)]
Learn more about Equation here:
brainly.com/question/2263981
#SPJ1
I don’t know
Igditditditd
Answer:9
Step-by-step explanation:
I looked up the average and it said 9.
Good luck on the rest of quarantine homework! :D
Mark brainliest if u want. ONLY if u want :D