Question

Solve the quadratic linear below :6x²-x-2=0​

Answer 1

Answer:

x = 3/2; x = -1/2

Step-by-step explanation:

6x² - x - 2 = 0

⇔ 6x² - 4x + 3x - 2 = 0

⇔ (6x² - 4x) + (3x - 2) = 0

⇔ 2x(3x - 2) + (3x - 2) = 0

⇔ (3x - 2)(2x + 1) = 0

⇔$\left \{ {{3x - 2=0} \atop {2x + 1=0}} \right.$

⇔$\left \{ {{3x=2} \atop {2x=-1}} \right.$

⇔$\left \{ {{x=2/3} \atop {x=-1/2}} \right.$

Answer 2

Answer:

$x 1= \frac{ + 1 + \sqrt{ { (- 1)}^{2} - 4 \times 6 \times ( - 2)} }{ 12} = \frac{8}{12} \\ x = \frac{ + 1 - \sqrt{ { (- 1)}^{2} - 4 \times 6 \times ( - 2)} }{ 12} = \frac{ - 6}{12}$