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Usimov [2.4K]
3 years ago
11

Solve the quadratic linear below :6x²-x-2=0​

Mathematics
2 answers:
Advocard [28]3 years ago
6 0

Answer:

x = 3/2; x = -1/2

Step-by-step explanation:

6x² - x - 2 = 0

⇔ 6x² - 4x + 3x - 2 = 0

⇔ (6x² - 4x) + (3x - 2) = 0

⇔ 2x(3x - 2) + (3x - 2) = 0

⇔ (3x - 2)(2x + 1) = 0

⇔\left \{ {{3x - 2=0} \atop {2x + 1=0}} \right.

⇔\left \{ {{3x=2} \atop {2x=-1}} \right.

⇔\left \{ {{x=2/3} \atop {x=-1/2}} \right.

Luda [366]3 years ago
5 0

Answer:

x 1=  \frac{ + 1 +  \sqrt{  { (- 1)}^{2}  - 4 \times 6 \times ( - 2)}  }{ 12} =  \frac{8}{12}  \\ x =  \frac{ + 1  -   \sqrt{  { (- 1)}^{2}  - 4 \times 6 \times ( - 2)}  }{ 12} =  \frac{ - 6}{12}

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