If the ratio of men to women is 3:2 and there are 120 men, how many women would there be?
2 answers:
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Answer: <em>third from the top</em>
Step-by-step explanation:
<em>The correct answer is third from the top.</em>
<em>Arranging numbers in ascending order: </em>
<em>15 17 17 17 18 18 18 19 19 19 21 21 22 23 24</em>
<em>Let's count how many times each number occurs in this series of numbers.</em>
<em>row of numbers</em>
<em>15 </em>+
<em>16 not</em>
<em>17 </em>+ + +
<em>18 </em>+ + +
<em>19 </em>+ + +
<em>20 not</em>
<em>21 </em>+ +
<em>22 </em>+
<em>23 </em>+
<em>24 </em>+
<em>25 not</em>
Answer:
Refer to image below:
Step-by-step explanation:
Answer:
The length of sides of one square is 5cm and length of sides of another square is 9cm
Step-by-step explanation:
Let the length of rectangle be x and width of rectangle be y.
We have given,
Area of rectangle = 45 cm²
i.e. Area of rectangle = x·y = 45 or xy = 45 ---------(1)
Next, two squares are constructed from two adjacent sides of rectangle.
i.e Side length of one square will be x and side length of another square will be y.
Area of one square = x²
And area of another square = y²
According to problem,
Sum of area of two squares is 106 cm²
∴ x²+y² = 106 ---------------(2)
From equation (1) and (2) , we can find x and y.
xy = 45 or x = , Plug this in equation (2).
We get,
x² + y² = 106
or
or
or
On solving this equation we get ,
y²=81 or 25
or y = 9 or 5
for y =9 , x=
or for y = 5 , x =
Hence the length of sides of one square is 5cm and length of sides of another square is 9cm