find the area of the trapezium whose parallel sides 24 cm and 20 cm and the distance between them is 15 cm.
1 answer:
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Answer:
8 (7.94)
Step-by-step explanation:
You can think of it as a geometry problem.
What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).
What you need to find is the height. We will call it H.
As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:
H^2 + 9^2 = 12^2
H^2 + 81= 144
H^2 = 63
Applying squared root in both sides
H = √63
H = 7,94
So, the height is approximately 8.
Answer:
158ft²
Step-by-step explanation:
Break it up!
Find the area of the three smaller shapes and add them together!
12+18+128= 158
