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tatyana61 [14]
3 years ago
10

Help? also explain pls

Mathematics
2 answers:
NikAS [45]3 years ago
7 0

Answer:

164 ft²

Step-by-step explanation:

We can divide the figure into a rectangle and a trapezoid. Find their areas and add them up.

Area of the rectangle

= 8×16

= 128 ft²

Area of the trapezoid

= (2+8+2)×6 ÷2

= 36 ft²

Total area of the yard

= 128+36

= <u>164 ft²</u>

natulia [17]3 years ago
5 0

Answer:

158ft²

Step-by-step explanation:

Break it up!

Find the area of the three smaller shapes and add them together!

12+18+128= 158

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Denise read 38 more pages than Elaine. Elaine read a total of 90 pages. How many pages did Denise read? 128 118 68 52
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The function f(x)=2x+1 is defined over the interval [2, 5]. If the interval is divided into n equal parts, what is the value of
vodomira [7]

Answer:

  D.  5 +6k/n

Step-by-step explanation:

The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...

  3/n

Then the difference between the left end point of the interval and the value of  x at the right end of the k-th rectangle will be ...

  k·(3/n) = 3k/n

So, the value of x at that point is that difference added to the interval's left end:

  2 + 3k/n

The value of the function for this value of x is ...

  f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1

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4 0
3 years ago
Barbara earned $48 for 6 hours of work. At that rate how much would she earn for 8 hours of work?
GrogVix [38]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu
Svet_ta [14]

Answer:

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

V = \dfrac{1}{2}(bh)\times L

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

\dfrac{b}{h} = \dfrac{5}{7}

b=\dfrac{5}{7}h this can be substituted back in the volume equation

V = \dfrac{5}{14}h^2L

the rate of the water flowing in is:

\dfrac{dV}{dt} = 6

The question is asking for the rate of change of height (m/min) hence that can be denoted as: \frac{dh}{dt}

Using the chainrule:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

V = \dfrac{5}{14}h^2L

\dfrac{dV}{dh} = \dfrac{5}{7}hL

reciprocating

\dfrac{dh}{dV} = \dfrac{7}{5hL}

plugging everything in the chain rule equation:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6

\dfrac{dh}{dt}=\dfrac{42}{5hL}

L = 12, and h = 1 (when the water is 1m deep)

\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0
3 years ago
Read 2 more answers
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