No because Carmella rounded both of the numbers down. Because she rounded it down to 300+10 there will not be enough space
Hope this helps
Answer:
D. 5 +6k/n
Step-by-step explanation:
The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...
3/n
Then the difference between the left end point of the interval and the value of x at the right end of the k-th rectangle will be ...
k·(3/n) = 3k/n
So, the value of x at that point is that difference added to the interval's left end:
2 + 3k/n
The value of the function for this value of x is ...
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
Answer:
64
Step-by-step explanation:
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Answer:

the rate of change of height when the water is 1 meter deep is 21 m/min
Step-by-step explanation:
First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).
As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

this can be substituted back in the volume equation

the rate of the water flowing in is:

The question is asking for the rate of change of height (m/min) hence that can be denoted as: 
Using the chainrule:

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h


reciprocating

plugging everything in the chain rule equation:



L = 12, and h = 1 (when the water is 1m deep)


the rate of change of height when the water is 1 meter deep is 21 m/min