Let's solve this system of equations through substitution.
We have these two equations.
-7x-2y=14
6x+6y=18
Now let divide the second equation by 6.
6x+6y=18 ----> x+y=3
Next, let us move y to the right side of the equation.
x+y=3 -------> x=3-y (x equals 3-y)
Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.
-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)
We have a one variable equation now and can solve for y.
-7(3-y)-2y=14
-21+7y-2y=14
5y=35
y=7
Plug in 7 for y in any equation to find x.
x+y=3
x+7=3
x=-4
answer: x=-4, y=7
She gave away 8 apples because 13 minus 5 is 8
Answer:
1
Step-by-step explanation:
All are divisible by 1.
Answer:
ACF
Step-by-step explanation:
Given:
The polynomial is given as
Required:
We need to find quotient and remainder
Explanation:
By synthetic division
Final answer:
Quotient is
Remainder is 0
