Question

Need help solving this problem down below.​

Answer 1

Answer:

1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²

2 / Find the area of an isosceles Δ DEF:

The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft

So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²

3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²

Step-by-step explanation: