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3 years ago

HELP PLS Describe two real-life situations that could be represented by the graph below

Mathematics

2 answers:

aev [14]3 years ago

4 0

the amount you walk by the hour?

x axis- distance

y axis- hours

:))

Nikitich [7]3 years ago

3 0

when you get in your car and you start driving, you start at a speed of 0 and then your speed can be anything from 0 to the maximum speed of your car. If you graphed your speed during a trip, you would end up with one continuous curve for your graph. You won't have any breaks in the graph.

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The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

Ludmilka [50]

Answer:

$6 \times 10^{7}$

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = $10^{7}$

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = $6 \times 10^{7}$

4 0

3 years ago

-3/16 7/4 -3/8 in order from least to greatest

jonny [76]

Answer:

-3/8,-3/16,7/4

4 0

3 years ago

Read 2 more answers

60 is 45% of what number?

pshichka [43]

60 is 45 percent of about 133.

5 0

3 years ago

Read 2 more answers

Base of triangle exceeds the height by 4. If the area is 178.5 square inches, find the length of the base and the height of the

xxMikexx [17]

Area of a triangle:
A= (1/2)(bh)

In this problem we are given:
A= 178.5 $in^{2}$
b= h+4 in
h= UNKNOWN ("h")

Plug in our values into the area equation and solve for "h":
$A= \frac{1}{2} bh$
$178.5 = \frac{1}{2} ((h+4)h)$ (multiply each side by 2 to get rid of the 1/2)
$357 = ((h+4)h)$
$357 = h^{2} +4h$
$0= h^{2} +4h -357$
(357/21=17)
$0= (h+21)(h-17)$ (solve both inequalities separately)

$0= (h+21)$
$-21= h$ ( a negative height is not possible so, this answer is incorrect.)

$0=(h-17)$
$h=17 in$

Answer: base = (h+4)= (17+ 4) b= 21 in h= 17in

Please comment with any further questions! :)

5 0

3 years ago