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Fiesta28 [93]
3 years ago
15

Joseph's parents have planted two gardens. One is square and has an area of 25 ft 2. The other one has two sides equal to 2/3 of

one side of the square, and the other two sides equal to 5/2 of one side of the square.
A. Find the dimensions of the other garden. Explain how you found your answer.
B. Find the area of the other garden.
Mathematics
1 answer:
Tomtit [17]3 years ago
6 0
A. 15ft - 12ft

b.120ft2
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Grace bought a television for $329 and some DVDs for $5.75 each. Write and equations to find out how many DVDs grace bought if s
marishachu [46]

The total number of DVDs that she bough is 6

<h3>Linear equations</h3>

Linear equation are expression that has a leading degree of 1.

Let the price of each DVD be x such that if Grace bought a television for $329 and some DVDs for $5.75 each  and spent a total of $363.50, ten;

329 + 5.75x = 363.5

Subtract 329 from both sides

329 + 5.75x - 329 = 363.5 - 329

5.75x = 34.5

x = 34.5/5.75

x = 6

This shows that the total number of DVDs that she bough is 6

Learn more on linear equation here: brainly.com/question/2030026

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3 0
2 years ago
Given the graph of the function F(x) below, what happens to F(x) when x is a negative number with a large absolute value?
noname [10]

Answer:F(x) is a negative number with a small absolute value

Step-by-step explanation:

4 0
3 years ago
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(4200 + 75) + 5 = ( ? )+ (75+5)<br> What would make it true?
geniusboy [140]

Answer:

4200

Step-by-step explanation:

4280=(?)+80

So the answer is 4200

8 0
3 years ago
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Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

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