Ca(OH)₂ + H₂SO₄ ⇒ CaSO₄↓ + 2H₂O
Answer:
from the ph given find the negative of log of concentrations of hydrogen and hydroxyl ions in acid and base respectively..then write tghe no. of moles of hydrogen and hydroxide ions
Owls means a mammalian species
It is incorrect question
mass of N₂ = 25.76 g
mass of O₂ = 58.88 g
Explanation:
Nitrogen (N₂) will react with oxygen (O₂) to form trinitrogen tetroxide (N₂O₄).
N₂ + 2 O₂ → N₂O₄
number of moles = mass / molecular weight
number of moles of N₂O₄ = 85 / 92 = 0.92 moles
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
then X moles of N₂ react with Y moles of O₂ to produce 0.92 moles of N₂O₄
X = (1 × 0.92) / 1 = 0.92 moles of N₂
Y = (2 × 0.92) / 1 = 1.84 moles of O₂
mass = number of moles × molecular weight
mass of N₂ = 0.92 × 28 = 25.76 g
mass of O₂ = 1.84 × 32 = 58.88 g
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These are three questions.
Answer:
- Question 1) Find Kc at 25°C: 617
- Question 2) Find [H₂] at 340°C: <u>0.352 M </u>
- Question 3) Find [HI] at 445°C: <u>0.342 M</u>
Explanation:
I will start by copying the table for better understanding of the data and the work to do.
T(∘C) [H2] [I2] [HI] [Kc]
25 0.0355 0.0388 0.922 -
340 4.60×10⁻²M 0.394M 9.6
445 4.90×10−2M 4.76×10⁻²M − 50.2
The chemical equation that represents the equilibrium is also given:
From that equilibrium equation, you can fnd the expression of the equlibrium constant, Kc, as:
![Kc=[HI]^2/([H_2][I_2])](https://tex.z-dn.net/?f=Kc%3D%5BHI%5D%5E2%2F%28%5BH_2%5D%5BI_2%5D%29)
The calculations and explanations to answer the three questions are in the pdf file attached.
Please, click on the image of the file to open it.
