Answer:
Line 2: for numF in [3, 5]
Line 1: for numE in [2, 6]
Line 3: print(numE, numF)
Explanation:
From the outputs, the first number of the first output is 2. This means that <em>numE in [</em><em>2</em><em>, 6]</em> would be on the first line.
The second number of the first output is 3, concluding that <em>numF in [</em><em>3</em><em>, 5]</em> is within a nested loop, meaning it would be on the second line.
This leaves <em>print(numE, numF)</em> on line 3.
We can go through the lines step by step to check if we have placed them in the correct order:
Code
for numE in [2, 6]:
for numF in [3, 5]:
print(numE, numF)
During the first iteration, numE = 2 and numF = 3.
Output: 2, 3
Since [3, 5] is in a nested loop, we need to finish iterating all of its numbers before numE moves to the next number, so:
numF moves to 5, numE stays at 2.
Output: 2, 5
Since we have finished iterating through [3, 5], numE moves to 6 and numF starts back at 3:
Output: 6, 3
numE still stays at 6 and numF iterates to 5 since [3, 5] is in a nested loop:
Output: 6, 5
The outputs match the outputs on the sheet, meaning we have correctly placed the code in order.
Hope this helps :)
