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yuradex [85]
3 years ago
8

For a class Foo, one difference between a variable declared Foo * and a variable declared Foo & is that only the variable de

clared Foo & can potentially have the value NULL.
Select one:

a. FALSE

b. TRUE
Computers and Technology
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

False.

Explanation:

When we declare a variable as reference type we have to initialize that variable otherwise the compiler will give error that the reference variable is not initialized.You also cannot initialize the variable Foo& with NULL value because it is a reference variable and we have to initialize it.

On the other there is no need to initialize the variable Foo * since it is a pointer it can also store NULL value.

So the answer is only Foo* can store NULL value not Foo &.

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I hope this answers your question.

Thank you,
Otaku
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List 5 ways by which Artificial intelligence (AI) can be used to drive our business.​
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Answer:

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Explanation:

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3 years ago
Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo
kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int n,no_open=0;

   cout<<"enter the number of lockers:";

   // read the number of lockers

   cin>>n;

   // initialize all lockers with 0, 0 for locked and 1 for open

   int lock[n]={};

   // toggle the locks

   // in each pass toggle every ith lock

   // if open close it and vice versa

   for(int i=1;i<=n;i++)

   {

       for(int a=0;a<n;a++)

       {

           if((a+1)%i==0)

           {

               if(lock[a]==0)

               lock[a]=1;

               else if(lock[a]==1)

               lock[a]=0;

           }

       }

   }

   cout<<"After last pass status of all locks:"<<endl;

   // print the status of all locks

   for(int x=0;x<n;x++)

   {

       if(lock[x]==0)

       {

           cout<<"lock "<<x+1<<" is close."<<endl;

       }

       else if(lock[x]==1)

       {

           cout<<"lock "<<x+1<<" is open."<<endl;

           // count the open locks

           no_open++;

       }

   }

   // print the open locks

   cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0
3 years ago
Date:<br>Difference between Chemical Equivalent and Electroche-<br>mical equivalent.​
Sergio039 [100]

Answer:

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5 0
3 years ago
When working with a large worksheet, you can split the window into ____ panes.?
krek1111 [17]
When working with a large worksheet, you can split the window into two or four panes.
5 0
3 years ago
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