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Yanka [14]
3 years ago
7

Give a tight bound on the number of times the z = z + 1 statement is executed. i = 2 while ( i > 1 ) { i = floor(i/2) z = z +

1 }
Computers and Technology
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

zero ( 0) times.

Explanation:

In the code;

i = 2

while ( i > 2){

     i = floor( i/2 );

     z = z + 1;

}

the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.

But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.

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