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Rus_ich [418]
2 years ago
9

Please help me!!!!!!!!!!!!!!!!

Mathematics
2 answers:
lara31 [8.8K]2 years ago
8 0

Answer:

what am i helping you with?

Step-by-step explanation:

girl did he cheat.... ITS A FREE PASS GET TO GOING GIRL

Nimfa-mama [501]2 years ago
5 0

Answer:

who where when what how?!!?

Step-by-step explanation:

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tester [92]

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Step-by-step explanation:

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Read 2 more answers
Verify the trigonometric identities
snow_lady [41]
1)

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\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2&#10;\\\\\\\&#10;[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]&#10;\\\\\\&#10;2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)&#10;\\\\\\&#10;\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}&#10;\\\\\\&#10;\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}&#10;\\\\\\&#10;\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}&#10;\\\\\\&#10;\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
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3 years ago
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