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joja [24]
2 years ago
5

Why is 3 1/2 multipiled by x in the equation

Mathematics
2 answers:
bagirrra123 [75]2 years ago
5 0

Answer:

I don't know the equation, but I will assume that 3 1/2 is the slope.

Step-by-step explanation:

For example, in the equation y = 10x - 9, the slope is 10.

Svetllana [295]2 years ago
5 0

Answer:

3 1/2 x is multiplied by x In the equation because it is the coefficient, the number being multiplied by the variable

Step-by-step explanation:

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Please help me, I know it’s not the first one but I think it’s the last one. Can somebody please confirm or deny?
GaryK [48]

Answer:

B. 2.2π m² : 3.2π m²

Step-by-step explanation:

Given:

Slant height (l) = 2.2 m

Diameter (d) = 2 m

Radius (r) = ½(2) = 1 m

Required:

Lateral area and surface area

Solution:

✔️Formula for lateral area of a cone = πrl

Plug in the values

Lateral area of the cone = π*1*2.2

Lateral area = 2.2π m²

✔️ Formula for surface area of a cone = πr(l + r)

Plug in the values

Surface area of the cone = π*1(2.2 + 1)

Surface area = π(3.2)

Surface area = 3.2π m²

The answer would therefore be:

2.2π m² : 3.2π m²

7 0
2 years ago
11] You buy a house for $175,000. The economy goes
DENIUS [597]

Answer:

4% of 175,000 is 7,000

7,000x 5=35,000

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7 0
2 years ago
Help me with this one
vaieri [72.5K]
Plant (A) have a higher median at 6 and the IQR is low at 3, however, Plant (B) has a lower median of 5 but High IQR of 4 so the Plant (B) is growth is high.
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3 years ago
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grandymaker [24]
Area of a circle = πr²

Area of a circle = 3.14 x 11² = 379.94 in²

Area painted in blue = 379.94 ÷ 2 = 189.97 in²

Area painted in purple = 189.97  in²

--------------------------
Answer: 189.97 in²
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4 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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