The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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QUESTION A:</h3>
Graph B.
The information is presented most clearly here, being centered and climbing steadily which prevents the influence of bias in the presentation. As stated, his presentation is intended to be neutral.
<h3>
QUESTION B:</h3>
Graph C.
This graph tricks the human brain into thinking that the increase is less prominent than we might perceive it in Graph A or B. This is because it is located lower and has a shallower slope. The campaign that wants to prevent immediate radical action (action which would harm the native species) would want to use this one as it might convince the city counsel that the issue is not urgent enough to take such actions so quickly.
There were exactly 31 people in chess club in 2002
I believe that the answer is B
