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Alex Ar [27]
2 years ago
7

Find the number, d, if the sum of five times d and five times five is a hundred.

Mathematics
1 answer:
Gelneren [198K]2 years ago
6 0

The value of d from the given expression is 15

<h3>Word problem leading to equation</h3>

From the given statement the sum of five times d and five times five is a

hundred is interpreted as;

5d + 5(5) = 100

5d + 25 = 100

Subtract 25 from both sides

5d = 100 - 25

5d = 75

d =15

Hence the value of d from the given expression is 15

Learn more on word problem here: brainly.com/question/13818690

#SPJ1

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Will mark BRAINLIEST!!!
svlad2 [7]

Answer:

answer choice c is correct

:)

hope that helped. <3

<em>bye now! </em>

<em>have a nice day too <3.</em><u><em> k bye</em></u>

7 0
3 years ago
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A satrellite moves at a speed of 27,000 kilometers per hour. Write four numbers that could be the actual speed of the satellite?
Maurinko [17]
Some satellites are up to 13,482,567 or 30,098,766 or 80,453,872 or even 900,435,879
8 0
3 years ago
For f(x)=4x+1 and g(x) = x^2 - 5, find (f+g)(x).
Rus_ich [418]

Answer:

(f + g)(x) = x² + 4x - 4  

Step-by-step explanation:

The statement (f + g)(x) is the same as f(x) + g(x). In other words, the question simply wants you to add the two functions together.

f(x) = 4x + 1

g(x) = x² - 5

(f + g)(x)                                  <----- Original statement

f(x) + g(x)                                <----- Rewrite

(4x + 1) + (x² - 5)                     <----- Substitute the equations in f(x) and g(x)

4x + x² - 4                              <----- Add 1 and -5

x² + 4x - 4                              <----- Rearrange the terms

3 0
1 year ago
Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0
artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2  + \frac{d^2f(0,0)}{dydx} x*y

So let's find all the terms:

Remember that:

\frac{dsin(ax)}{dx}  = a*cos(ax)

\frac{dcos(ax)}{dx} = -a*cos(ax)

f(0,0) = sin(0*0) = 1.

\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y

\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y

\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 =  -\frac{1}{2}  *y^2*sin(0*0)*x^2 = 0

\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 =  -\frac{1}{2}  *x^2*sin(0*0)*y^2 = 0

\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0
3 years ago
Factor the following expression<br><br> 28w^(4)x^(2)y^(7)+12w^(9)x^(8)
disa [49]

The expression after factorisation is 4w⁴x² (7y⁷ + 3w⁵x⁶)

<h3>What is an Expression ?</h3>

An expression is defined as a mathematical statement consisting of variables , constants and mathematical operators.

The expression given is

28w⁴x²y⁷+12w⁹x⁸

Factors of the given expression will be the common terms in both the terms

w⁴x² is common in the variable term

The HCF of 28 and 12 is 4

4w⁴x² (7y⁷ + 3w⁵x⁶)

The expression after factorisation is 4w⁴x² (7y⁷ + 3w⁵x⁶)

To know more about Expression

brainly.com/question/14083225

#SPJ1

6 0
1 year ago
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