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Alex Ar [27]
2 years ago
7

Find the number, d, if the sum of five times d and five times five is a hundred.

Mathematics
1 answer:
Gelneren [198K]2 years ago
6 0

The value of d from the given expression is 15

<h3>Word problem leading to equation</h3>

From the given statement the sum of five times d and five times five is a

hundred is interpreted as;

5d + 5(5) = 100

5d + 25 = 100

Subtract 25 from both sides

5d = 100 - 25

5d = 75

d =15

Hence the value of d from the given expression is 15

Learn more on word problem here: brainly.com/question/13818690

#SPJ1

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Answer:

$2.40 or $77.55

Step-by-step explanation:

I don't know if you are asking for how much off or what, so I'm doing both

First, we have to find how much we have to take off or what is 30% of 79.95 so our equation is:

79.95 x 0.03 = 2.40

So 30% of 79.95 is $2.40

To find how much our new price sale is, we have to take that $2.40 off so our equation is:

79.95 - 2.4 = 77.55

So our discount price is $77.55

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Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr
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Answer:

f(x) = 3 \cdot 0.2^x

Step-by-step explanation:

f(x) = 3 \cdot 0.2^x


Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is \mathbb{R}

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore (0, \infty).

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe f(x-1) > f(x) for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies f(x) < 0.

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End behaviour: As x \rightarrow \infty, f(x) \rightarrow 0. As x \rightarrow -\infty, f(x) \rightarrow +\infty

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3 years ago
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