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Alex Ar [27]
1 year ago
7

Find the number, d, if the sum of five times d and five times five is a hundred.

Mathematics
1 answer:
Gelneren [198K]1 year ago
6 0

The value of d from the given expression is 15

<h3>Word problem leading to equation</h3>

From the given statement the sum of five times d and five times five is a

hundred is interpreted as;

5d + 5(5) = 100

5d + 25 = 100

Subtract 25 from both sides

5d = 100 - 25

5d = 75

d =15

Hence the value of d from the given expression is 15

Learn more on word problem here: brainly.com/question/13818690

#SPJ1

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In the town zoo 3/8 of the animals are birds. Of the birds 4/15 are birds of prey. What fraction of the animals are nirds of pre
poizon [28]
<span>3/8 of the animals are birds<span>
of the birds: 4/15 are birds of prey

If you want to know what fraction of the animals at the zoo are birds of prey, you can calculate this using the following steps:

4/15 * 3/8 <span>= 12 / (15*8) = </span>1 / (5*2) <span>= </span>1 / 10 = 0.1

<span>Result: In the town zoo, </span>1/10 of animals are birds of prey<span>.</span></span></span>
5 0
2 years ago
(50 Points Please help)
Elina [12.6K]

Answer:

A. Length of a Tour Bus                       ↔     #2.      1.1 × 10¹ meters

B. Width of an apple                             ↔      #3.     4 × 10⁰ centimeters

C. Distance from Earth to a Satellite    ↔    #6.     8 × 10² kilometers

D. Thickness of a human hair               ↔     #5.      9 × 10¹ micrometers

Step-by-step explanation:

The length of a tour bus should be measured in meters. It sure is way less than 1 kilometer and way more than a few centimeters. It could be about some meters, more than 5 meters, may be between 10 meters and 15 meters.

The measurement in the box # 2. is 1.1 × 10¹ meters, which is equivalent to 1.1 × 10 meters = 11 meters. Thus, this is a reasonable length.

B. Width of an apple.  

The most appropriate unit to measure the width of an apple should be centimeter. It certainly is shorter than 1 meter and bigger than 1 mm.

The width of an apple could be, more or less, around 8 centimeters. The only measurement in the boxes that is in that order is that in the box #3., 4 × 10⁰ centimeters, because 10⁰ = 1, so 4 × 10⁰ = 4 × 1 = 4 centimeters.

C. Distance from Earth to a Satellite

The distance from Earth to a satellite should be measured in kilometers.

You can find in the internet that the distances of the satellites are between 700 kilometers and 36,000 kilometers.

The number in the box #1 is too big, in the order of ten trillions of kilometers, because one trillion is 10¹²; thus that is nonseasonal (too big).

The number in the box #6 is  8 × 10² kilometers, which is equal to 8 × 100 = 800 kilometers.

Thus,  8 × 10² kilometers (box #6) is the most reasonable measurement for the distance from Earth to a Satellite

D. Thickness of a human hair

Of course, kilometers, meters, centimeters and even millimeters are units too big to measure the thickness of a human hair.

One micrometer is 10⁻⁶ meters or 10⁻³ millimeters.

In the internet you can find that diameter of the human hair is in the range from 17 micrometers to 181 micrometers.

The measurement in the box #5. is 9 × 10¹ micrometers, which is equivalent to 9 × 10 = 90 micrometers.

Thus, 9 × 10¹ micrometers is the most reasonable measurement for the thickness of a human hair.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!:)). The area of ​​the trampezoid is 100dm and the bases are 2.1m and 1.9m. Calculate the height of the trampezoid
mixas84 [53]

Answer:

Well, the only thing you should do is to use the formula.

if the bases are: a, b

and the height is=h

Then, this is your formula, S=½(a+b)×h

Step-by-step explanation:

Aight,

100dm=10m

S=10m

now, the formula

10=½(2.1+1.9)×h===> 20=4h==> h=5m

5 0
2 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
Bababoe pls help meeee
mihalych1998 [28]

Answer:

Exact answer is 0.00076232

Step-by-step explanation:

i can give give u a website that does this, if u want

3 0
2 years ago
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