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bagirrra123 [75]
3 years ago
12

At a high school, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school

?​
Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

40 minutes

2/3 hours

0.667 hour

2,400 seconds

Step-by-step explanation:

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Juans three math quizzes this week took him 1/3?4/6?and1/5 hour to complete. List all the fraction from least to greatest
Alex

Answer:

\frac{1}{5} ,  \frac{1}{3} , \frac{4}{6}.

Step-by-step explanation:

Given fractions \frac{1}{3}, \frac{4}{6}, \frac{1}{5}.

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of  \frac{1}{3}, \frac{4}{6}, \frac{1}{5}.

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

Let us covert each denominator as 30.

Multiplying first fraction \frac{1}{3} by 10 in top and bottom, we get

\frac{1}{3} = \frac{1\times10}{3\times10}=\frac{10}{30}

Multiplying first fraction \frac{4}{6} by 5 in top and bottom, we get

\frac{4}{6} = \frac{4\times5}{6\times5}=\frac{20}{30}

Multiplying first fraction  \frac{1}{5} by 6 in top and bottom, we get

\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.

Now, we can check \frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.

\frac{6}{30} is the smallest, \frac{10}{30} is greater and \frac{20}{30} is the greatest.

Therefore, we can arrange fractions\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.

Writing original fractions in place of equivalent fractions, we can write

\frac{1}{5} ,  \frac{1}{3} and  \frac{4}{6}.

Therefore, the order the amounts of paint from least to greatest is:

\frac{1}{5} ,  \frac{1}{3} , \frac{4}{6}.




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3 years ago
Solve the system algebraically.<br><br>y=3-1/2x<br><br>3x+4y=1<br><br>what is the value of x?
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Use the expression for y in the second equation.
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3 years ago
Solve the proportion x/12.6=45/63
NNADVOKAT [17]

Answer:

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Step-by-step explanation:

solve using cross multiplication

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