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3 years ago

What is the vertex of the GraphMATH 1 PLEASE HELP

Mathematics

1 answer:

Pie3 years ago

7 0

I can't see the problem so repost it and tag me in it

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Val walks 2 3/5 miles each day.bill runs 10 once every 4 days.in 4 days.who covers the greater distance?

Mkey [24]

Answer: Val walks the greater distance. She walks 2/5 miles more than Bill. Hope this helps!

Step-by-step explanation:

6 0

3 years ago

19,432÷x=48 Remainder 232 (Plz help its for my hw that's due tmrw)

Neko [114]

Answer:

x = 404.83

Step-by-step explanation:

The given expression is :

19,432÷x=48 ...(1)

We need to find the value of x.

$\dfrac{19,432}{x}=48$

Cross multiplying both sides,

$19,432=48x$

Dividing both sides by 48

$\dfrac{19,432}{48}=x\\\\x=404.83$

So, the value of x is 404.83.

4 0

2 years ago

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Find the missing lengths in the given triangle

katovenus [111]

90° becuase 60+30 = 90 and 90+90=180

3 0

3 years ago

Dilate Point B by a scale factor of 1/2

Sauron [17]

Answer:

Step-by-step explanation:

Divide each coordinate by 2

3/2=1.5

2/2=1

8 0

3 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

Read 2 more answers