Answer:
L= 24cm
W= 4cm
Step-by-step explanation:
Given data
Perimeter= 56cm
Area= 96cm^2
Let the width be x
W= x cm
L= 5x+4
P=2L+2W
56= 2(5x+4)+2x
56= 10x+8+2x
56-8= 12x
48= 12x
x= 48/12
x= 4cm
L= 5x+4
L= 5(4)+4
L= 20+4
L= 24cm
2(2x-3) + 2(x+6) = P
(4x - 6) + (2x + 12) = P
6x + 6 = P ~answer~
(2x-3)(x+6) = A
2x^2 + 12x -3x - 18
2x^2 + 9x - 18 = A. ~answer~
Answer:Fred has 13 9/10 minutes left for question C
Step-by-step explanation:
The total time that Fred has to do the three-problem quiz is 30 minutes.
He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.
He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.
Total time that Fred spent on question A and question B is
107/10 + 27/5 = (107 + 54)/10
= 161/10 minutes.
The amount of time that he has left for question C would be
30 - 161/10 = (300 - 161)/10 = 139/10
= 13 9/10 minutes
Answer:
The equation is
whose solution is ![m =120\:minutes.](https://tex.z-dn.net/?f=m%20%3D120%5C%3Aminutes.)
Step-by-step explanation:
Let us call
the number of minutes the phone is used over 200 minutes, then we have
<em>(this says monthly bill of $40 plus the cost of phone usage over 200 minutes must equal $58 )</em>
This equation can be used to solve for
u as follows:
![0.15m = 58-40](https://tex.z-dn.net/?f=0.15m%20%3D%2058-40)
![m = \dfrac{18}{0.15}](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7B18%7D%7B0.15%7D)
![\boxed{m = 120\:minutes}](https://tex.z-dn.net/?f=%5Cboxed%7Bm%20%3D%20120%5C%3Aminutes%7D)