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maksim [4K]
3 years ago
10

Find the limit, if it exists. (if an answer does not exist, enter dne.) lim (x, y) → (0, 0) x4 − 20y2 x2 + 10y2

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0
Traveling along the x-axis, we have

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{x\to0}\frac{x^4}{x^2}=\lim_{x\to0}x^2=0

On the other hand, along the y-axis we get

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{y\to0}\frac{-20y^2}{10y^2}=\lim_{y\to0}(-2)=-2

Therefore the limit doesn't exist.
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How is 5/2 divided by 1/4 equals 10 responsible
vredina [299]

Answer:

Step-by-step explanation:

'll just help with proving whether she is correct.

First of all, a fraction divided by a fraction can be made into multiplication since the division of two fractions is kinda difficult

so remember keep, change, flip

keep the first fractions, change the division symbol into multiplication, then flip the fraction i.e. 1/2 becomes 2/1

so 5/2 divided by 1/4 becomes  

5/2 * 4/1

which then solved becomes

20/2 which is simplified to 10

Hope this helps :)

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