Answer:
SSS
∆PQR = 43
Step-by-step explanation:
The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.
9 + 6y + 5 + 14 = 9 + 8y +14
28 + 6y = 9 + 8y + 14
28 + 6y = 8y + 23
-6y -6y
--------------------------
28 = 2y + 23
-23 -23
---------------------
5 = 2y
---- ----
2 2
2.5 = y
9 + 14 + 6(2.5) + 5
23 + 15 + 5
23 + 20
43
∆PQR = 43
The circumference when the diameter is 18 = 18pi
The circumference when the diameter is 6 = 6pi
18pi/6pi=3
The circumference will become a third of what it was.
Hope this helps!
to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3
