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klasskru [66]
4 years ago
7

Two lines, A and B, are represented by the following equations:

Mathematics
1 answer:
laila [671]4 years ago
3 0
The fourth option shows the solution to the system of equations and explains why.
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Find sec Θ if the terminal side of Θ in standard position contains the point (4, -3)
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If we plot that point we find ourselves in QIV.  The distance along the x axis is 4, and the distance down from that point is -3.  If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle.  We need its measure.  Using Pythagorean's theorem, 4^2+-3^2=c^2 and 16+9=c^2.  We see that c = 5.  We need now to find the secant of that right triangle.  Secant if the co-identity of cosine which is side adjacent over hypotenuse.  That means that secant is the hypotenuse over the side adjacent.  So our secant theta = 5/4
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What is the area of the triangle when the sides are 6 7 and X
Sonbull [250]

Answer:

firgure it out yourself because no one helps me

Step-by-step explanation:

.

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3 years ago
Bought five lip balms. Each lip balm costs the same amount. She spent a
Juli2301 [7.4K]
The equation for your question would be 7.25= 5c :)
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3 years ago
Which recursive formula can be used to generate the sequence shown, where f(1) = 9.6 and n > 1?
Alenkasestr [34]

We have got an geometric progression.

We use to find any term of a geometric sequence, this equation:

an=a₁ * r^(n-1)

a₁= is the first term.

r=is the common ratio.

n=numbers of the term to find.


r=an / an-1

In this case:

r=a₂/a₁=(-4.8) / 9.6=-0.5

a₁=9.6


an=9.6*(-0.5)^(n-1)



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3 years ago
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