If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem,

and

. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
Answer:
firgure it out yourself because no one helps me
Step-by-step explanation:
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The equation for your question would be 7.25= 5c :)
We have got an geometric progression.
We use to find any term of a geometric sequence, this equation:
an=a₁ * r^(n-1)
a₁= is the first term.
r=is the common ratio.
n=numbers of the term to find.
r=an / an-1
In this case:
r=a₂/a₁=(-4.8) / 9.6=-0.5
a₁=9.6
an=9.6*(-0.5)^(n-1)