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larisa [96]
3 years ago
8

Bridge B is 165 feet shorter than Bridge A.The combined length of the two bridges 8421 feet. Find the length of each bridge

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Answer:4128 and 4293

Step-by-step explanation:

8421-165=8256

8256/2=4128

4128+165=4293

4293+4128=8421

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Allushta [10]

Answer:

why you color out the first part? what exctly is the question?

Step-by-step explanation:

6 0
3 years ago
Math/Physics Problem <br> (I'd be glad if you solved one of them).
Whitepunk [10]

Answer:

19.2

76.8

Step-by-step explanation:

density × volume = mass

mass = 62.4 × (pi × (40/2)² × h)

mass = 78,374.4h

WD = m×9.8×h = 9.8mh

WD = 768,069.12h²

At h = 5

WD = 768,069.12×5²

= 19,201,728 ft-lb

= 19.2 million ft-lb

At h = 10

WD = 76,806,9.12 × 10²

WD = 76,806,912 ft-lb

= 76.8 million ft-lb

4 0
3 years ago
HelPPPPP PLSSSSSSSSSSSSSSSSSSSSSSSS page 109 :((((((((((((((((((( ty!&lt;333
gavmur [86]

Answer:

1. 1/4+1/4=2/4=1/2

2. Yes

3. i don't know

4. Yes

Step-by-step explanation:

1. 1+1=2 therefore you get 2/4 or 1/2

2. 2/3 is the reduced form of 4/6

3. i honestly dont know

4. 3/4 is the reduced form of 9/12

5 0
2 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
You are running a concession stand at a basketball game. You are selling hotdogs and sodas. Each hotdog cost $1.50 and each soda
Lubov Fominskaja [6]

Answer:

35 hotdogs

Step-by-step explanation:

You are running a concession stand at a basketball game. You are selling hotdogs and sodas.

Let the number of hot dogs be represented by x

The number of soda be represented by y

You sold a total of 87 hotdogs and sodas combined

x + y = 87

x = 87 - y

Each hotdog cost $1.50 and each soda cost $0.50. At the end of the night you made a total of $78.50.

Hence we have the equation:

$1.50 × x + $0.50 × y = $78.50

1.50x + 0.50y = 78.50

Substitute 87 - y for x

1.50(87 - y) + 0.50y = 78.50

130.5 - 1.50y + 0.50y = 78.50

Collect like terms

- 1.50y + 0.50y = 78.50 - 130.50

-1.00y = -52

y = -52/-1

y = 52 sodas

How many hotdogs did you sell?

Using the equation:

x = 87 - y

x = 87 - 52

x = 35 hotdogs

Hence, you sold 35 hotdogs

6 0
3 years ago
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