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3 years ago

9

While shopping for clothes, Daniel spent $42 less than 3 times what Curtis spent. Daniel spent $21. Write and solve an equati

on to find how much Curtis spent. Let x represent how much Curtis spent.

1 answer:

ratelena [41]3 years ago

5 0

Answer:

$21

Step-by-step explanation:

21+42=63

x=63:3

x=$21

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Answer:

The circumference of the cake board is <u>35π cm</u>.

Step-by-step explanation:

The question is incomplete, so the complete question is below:

A round cake has a diameter of 30 cm. Angela places the cake on a circular cake board with a diameter 5 cm longer than that of the cake. What is the circumference of the cake board? Give your answer in terms of π.

Now, to find the circumference of the cake board.

As, given diameter of cake = 30 cm.

And diameter of cake board is 5 cm longer than that of the cake.

Thus, the diameter of cake board is:

$30\ cm+5\ cm=35\ cm.$

So, to find the circumference we need radius, by putting formula:

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Step-by-step explanation:

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Step-by-step explanation:

Move expression to the left side and change its sign

5

y

−

3

+

10

y

2

−

y

−

6

−

y

y

+

2

=

0

Write

−

y

as a sum or difference

5

y

−

3

+

10

y

2

+

2

y

−

3

y

−

6

−

y

y

+

2

=

0

Factor out

y

and

−

3

from the expression

5

y

−

3

+

10

y

(

y

+

2

)

−

3

(

y

+

2

)

−

y

y

+

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Factor out

y

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from the expression

5

y

−

3

+

10

(

y

+

2

)

(

y

−

3

)

−

y

y

+

2

=

0

Write all numerators above the least common denominator

5

(

y

+

2

)

+

10

−

y

(

y

−

3

)

(

y

+

2

)

(

y

−

3

)

=

0

Distribute

5

and

−

y

through the parenthesis

5

y

+

10

+

10

−

y

2

+

3

y

(

y

+

2

)

(

y

−

3

)

=

0

Collect the like terms

8

y

+

20

−

y

2

(

y

+

2

)

(

y

−

3

)

=

0

Use the commutative property to reorder the terms

−

y

2

+

8

y

+

20

(

y

+

2

)

(

y

−

3

)

=

0

Write

8

y

as a sum or difference

−

y

2

+

10

y

−

2

y

+

20

(

y

+

2

)

(

y

−

3

)

=

0

Factor out

−

y

and

−

2

from the expression

−

y

(

y

−

10

)

−

2

(

y

−

10

)

(

y

+

2

)

(

y

−

3

)

=

0

Factor out

−

(

y

−

10

)

from the expression

−

(

y

−

10

)

(

y

+

2

)

(

y

+

2

)

(

y

−

3

)

=

0

Reduce the fraction with

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+

2

−

y

−

10

y

−

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=

0

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−

y

−

10

y

−

3

=

0

Simplify

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−

y

y

−

3

=

0

When the quotient of expressions equals

0

, the numerator has to be

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−

y

=

0

Move the constant,

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y

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≠

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≠

−

2

∴

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=

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