6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
I think you are missing part of the problem. If you had another equation or a value for x you could solve it.
100/x=60/30 so x=100*30/60=50
Answer:the first one
Step-by-step explanation:Egd
Answer:
We see that opposite angles are two angles between two secant lines (“secant lines” simply means two lines that cross each other) that share a vertex (that is why they are called “vertical” angles). We see also that they are not adjacent (which means next to each other) but opposite each other.
Step-by-step explanation:
Vemos que los ángulos opuestos son dos ángulos entre dos líneas secantes (“líneas secantes” simplemente significa dos líneas que se cruzan) que comparten un vértice (por eso se llaman ángulos “verticales”). También vemos que no son adyacentes (lo que significa uno al lado del otro) sino uno frente al otro.
