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Anna [14]
3 years ago
8

Nakita recorded a video of homecoming highlights of the senior class and now everybody wants a copy. She promised to have 25 rea

dy the next day but suddenly realized that it will take her ten hours to do that. Her friend, Abby, volunteered to help and she can do the job alone in 15 hours. How long will it take the girls, working together, to complete the job?
Mathematics
1 answer:
Simora [160]3 years ago
5 0

Answer: 6hours

Step-by-step explanation:

it will take Nakita 10 hours to get 25 copies of the video ready

Then it takes Nakita 25/10 per hour to get 25 copies ready

it will take Abby 15 hours to get 25 copies of the video ready

Then it takes Abby 25/15 per hour to get 25 copies ready

It is assumed that they are working individually and simultaneously. This means their work rate is additive.

Their combined work rate per hour is

25/10 + 25/15 = 5/2 +5/3

=25/6 per hour

Let x hours be the time it will take them to get 25 videos ready.

It will take them 25/x per hour to get the videos ready

Equating both expressions,

25/x =25/6

25 × x = 25 × 6

x = 6 hours

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Nikolay [14]

Answer:

There are 8008 possible outcomes are there the first time he grabs 6 chocolates

Step-by-step explanation:

The order in which the chocolates are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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6 chocolates from a set of 16. So

C_{16,6} = \frac{16!}{6!(16 - 6)!} = 8008

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3 years ago
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The
ExtremeBDS [4]

Answer:

  • 800 kph
  • 600 kph

Step-by-step explanation:

<u>Equation</u>

Let s represent the speed of the faster plane. Then its travel time is ...

  time = distance/speed = 3600/s

travel time for the slower plane is ...

  time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

  3600/(s -200) -3600/s = 1.5

<u>Solution</u>

Multiplying by (2/3)s(s -200), we get ...

  2400(s) -2400(s -200) = s(s -200)

  s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

  (s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

<u>Conclusion</u>

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

<em>Check</em>

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

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Answer:

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Answer:

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Step-by-step explanation:

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7 0
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