I hope you guys can see it but if you answer it i’ll make you the brainiest
1 answer:
Answer:
Step-by-step explanation:
the smallest length that the pen could be is the with x length => 209 sq ft
where the length is 8 feet more than the width.
so find that where x *( x+8) = 209
then + 8x - 209 = 0
using the quadratic equation I got 11
11* ( 11+8) =209
so that's the smallest it could be
so the width must be greater than 11 to make the pen greater than 209 sq ft. :)
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The answer is 5/2. The equation is already in point slope form. If you recall, the equation for point slope form is y-y1 = m(x-x1) where y1 and x1 are points on the graph, and m is the slope. In the given equation, m is 5/2 so we know it is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.