Question

I hope you guys can see it but if you answer it i’ll make you the brainiest

Answer 1

Answer:

Step-by-step explanation:

the smallest length that the pen could be is the with x length => 209 sq ft

where the length is 8 feet more than the width.

so find that where x *( x+8) = 209

then  $x^{2}$ + 8x - 209 = 0

using the quadratic equation I got  11

11* ( 11+8) =209

so that's the smallest it could be

so the width must be greater than 11 to make the pen greater than 209 sq ft. :)