All categories

2 years ago

Rewrite in simplest terms 6(6r+8)-2r

Mathematics

1 answer:

Snezhnost [94]2 years ago

7 0

Answer:

34r+48

Step-by-step explanation:

36r+48-2r=34r+48

You might be interested in

The population of a certain species of bacteria doubles every hour. Use the following

elena55 [62]

Answer:

The bacteria will grow from 1 to 1024 in 10 hours

Step-by-step explanation:

Given

P_0 = 1

P = 1024

We have to find time

Putting values in the formula

$P = P_0(2)^t\\1024=(1)(2)^t$

Anything multiplied with 1 remains the same

$1024=2^t\\2^{10} = 2^t$

Using the property "when bases are same, the exponents can be put equivalent"

t = 10 hours

Therefore, the bacteria will grow from 1 to 1024 in 10 hours ..

7 0

2 years ago

1000^m / 100^n can be written in the form of 10^z express z in terms of m and n

Julli [10]

Answer:

z = 3m - 2n

Step-by-step explanation:

$\frac{ {1000}^{m} }{ {100}^{n} } = {10}^{z} \\ \\ \frac{ {10}^{3m} }{ {10}^{2n} } = {10}^{z} \\ \\ {10}^{3m - 2n} = {10}^{z} \\ \\ 3m - 2n = z \\ \\ \huge \red{ \boxed{z = 3m - 2n}}$

5 0

2 years ago

Solve the equation and check the solution 7/80=-1/8g

algol13

Answer:

Exact Form: g= -7/10

Decimal Form: g= -0.7

Step-by-step explanation:

Hope this helped

7 0

3 years ago

I NEED HELP ON BOTHHH PLEASE

Maksim231197 [3]

Answer:

what does the picture say i cant see the picccccccc

Step-by-step explanation:

8 0

2 years ago

A superhero is rendered powerless when exposed to 3535 or more grams of a certain element. A 550550 year old rock that originall

bazaltina [42]

Answer:

(a)

The quantity of element that are still contained in the stolen rock

is 37.1627g

(b)

this rock can be used by the superhero's nemesis to render the superhero powerless is 567 years

Step-by-step explanation:

We are given

original quantity =250g

half life time =200 years

so, we can use formula

$P(t)=P_0(0.5)^{\frac{t}{h} }$

where

Po is initial quantity

h is half life time

t is time in years

so, we can plug h=200 and Po=250

and we get

$P(t)=250(0.5)^{\frac{t}{200} }$

(a)

we can plug t=550

and then we can find P(t)

$P(550)=250(0.5)^{\frac{550}{200} }$

we get

$P(550)=37.1627g$

(b)

we can set P(t)=35

and then we can solve for t

$35=250(0.5)^{\frac{t}{200} }$

$0.5^{\frac{t}{200}}=\frac{7}{50}$

we can take ln on both sides

$\ln \left(0.5^{\frac{t}{200}}\right)=\ln \left(\frac{7}{50}\right)$

$t=\frac{200\ln \left(\frac{7}{50}\right)}{\ln \left(0.5\right)}$

$t=567.3$

$t=567$ years

6 0

2 years ago