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3 years ago

Draw a line segment AB of length 6.6 cm. Bisect it perpendicularly at N using a

Mathematics

1 answer:

tamaranim1 [39]3 years ago

6 0

Step-by-step explanation:

If a line segment AB of length 6.6cm is drawn, bisecting it perpendicularly at N, we have two lines AN and NB of length 3.3cm each.

Because the line is bisected perpendicularly, the angles formed at the point of bisection are 90 degrees.

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If 22+4=24 13+6=16 80+2==82 then 67+9= what

Anon25 [30]

Step-by-step explanation:

after seeing your method of your addition I can answer it like 69....

hope it helps....

4 0

3 years ago

A–2=3+6a/3<br> What dose a equal?

balandron [24]

Answer:

a = -5

Explanation:

7 0

3 years ago

Read 2 more answers

Tahmar knows the formula for simple interest is I = Prt, where I represents the simple interest on an amount of money, P, for t

rewona [7]

Answer:

P = $80

Step-by-step explanation:

I = P*r*t

P = I/rt

Where,

simple interest, I = $20

Interest rate, r = 5%

Time, t = 5 years

P = I / rt

= 20 / 5% * 5

= 20 / 0.05 * 5

= 20 / 0.25

= 80

P = $80

3 0

3 years ago

What is the average of 5,0,12,9

Mila [183]

6.5 because you add up all your numbers and then divide by the amount of numbers you added
5+0+12+9=26
26/4=6.5

6 0

3 years ago

Read 2 more answers

A recursive rule for a geometric sequence is a1=2; an= 4/9 an-1

Oxana [17]

A recursive rule for a geometric sequence:

$a_1\\\\a_n=r\cdot a_{n-1}$

---------------------------------------------------

$a_1=2;\ a_n=\dfrac{4}{9}a_{n-1}\to r=\dfrac{4}{9}$

---------------------------------------------------

The exciplit rule:

$a_n=a_1r^{n-1}$

Substitute:

$a_n=2\left(\dfrac{4}{9}\right)^{n-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\left(\dfrac{4}{9}\right)^{-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\dfrac{9}{4}\\\\\boxed{a_n=\dfrac{9}{2}\cdot\left(\dfrac{4}{9}\right)^n}$

3 0

3 years ago