Find the perimeter of a square with a side length of 4x
1 answer:
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A' (3(-5),3(-4))= (-15,-12)
B' (3(2),3(6))=(6,18)
C'(3(4),3(-3))=(12,-9)
I found this since im really bad at explaining
One thing you should notice is that the transverse line and the parallel line form a right triangle. We are told that the base is 4 and the angle between the hypotenuse and the leg is 45°
From this we can solve for the second leg. Here's the list of trig functions
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get
Multiply by 4 to isolate x and we get
= x
Hopes this helps!
From this we can solve for the second leg. Here's the list of trig functions
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get
Multiply by 4 to isolate x and we get
Hopes this helps!