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Len [333]
2 years ago
9

How many times can 64 go into 84

Mathematics
2 answers:
hoa [83]2 years ago
5 0
Once and with 20% remainder
Juliette [100K]2 years ago
3 0
64 only goes into 84 once
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Write an equation for the line that is parallel to the given line and that passes through the given point.
Rasek [7]
Parallel to y = 3/4x - 9 and passes through (-8, -18)

Identify the slope : our slope is 3/4

Remember that parallel equations have the same slope, so both slopes are 3/4

Now, we have to find the y-intercept. Simply plug everything into the slope intercept form equation.

y = mx + b

(-18) = (3/4)(-8) + b

Simplify.

-18 = -6 + b

Add 6 to both sides.

-18 + 6 = b

Therefore, our y-intercept is -12.

Now plug everything into the slope intercept form.

y = mx + b

y = 3/4x - 12

~Hope I helped!~
4 0
2 years ago
A car can drive 476 miles on 14 gallon
Degger [83]
What is the question?
8 0
3 years ago
Which of the following is equivalent to log50^7 rounded to three decimal places
Vitek1552 [10]

Answer:

11.886

Step-by-step explanation:

Given :

log 50^7

Applying formula

log a^m=m log a

So,

7 log 50\\=7(1.698)\\=11.886

Answer will be 11.886

3 0
3 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)? A) 54.5 B) 42.634 C) 39.5 D) 27
beks73 [17]

Answer:

D

Step-by-step explanation:

First add all the simple line up so;

8 + 7 + 3 + 2 = 20

Then use Pythagoras to work out the lengths of the remaining lines

\sqrt{ {2}^{2}  +  {4}^{2} }   = 2 \sqrt{5}  \\  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\ 20 +  \sqrt{10}  + 2 \sqrt{5} = 27.63441362

So to three decimal places it would be;

27.634

7 0
3 years ago
What is the domain, range, and function? {(-3, 3), (1, 1), (0, -2), (1,4), (5, -1)}
wolverine [178]

The domain are all the inputs, that is; the x-values

Domain = { -3, 0, 1, 5}

The range are all the output, that is the y-values

Range = { 3, 1, -2, 4, -1}

This is just a relation and not a function, as we have more than 2 same value of x

8 0
10 months ago
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