Answer:
Dimension of cardboard is 22 m by 16 m
Explanation:
Given that,
Area = 352 cm²
Side of each square cutting from corner = 2 cm
Volume of box = 432 cm³
Let the two sides are x and y.
The area of the rectangular piece is
-------- (1)
The volume of the rectangular piece
x=16,22
Put the value of x in the equation (I)
For x = 16
For x = 22
Dimension of cardboard is 22 m by 16 m
Answer:
451.13 J/kg.°C
Explanation:
Applying,
Q = cm(t₂-t₁)............... Equation 1
Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.
Make c the subject of the equation
c = Q/m(t₂-t₁).............. Equation 2
From the question,
Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C
Substitute these values into equation 2
c = 1500/[0.133(45-20)]
c = 1500/(0.133×25)
c = 1500/3.325
c = 451.13 J/kg.°C
When minerals are exposed to high pressure and temperatures, the individual minerals begin to realign themselves