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Pavel [41]
3 years ago
13

For each scenario below, choose the best graph. (a) Maria bikes from home to work.

Physics
1 answer:
BlackZzzverrR [31]3 years ago
5 0

A line graph that plots either speed or distance against time.

Really, the type of graph depends on what quantity you want the graph to show.

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What happens when an immovable object meets an unstoppable force?”
Alisiya [41]

Answer:

Sorry to tell you this but there’s no answer for that

Explanation:

4 0
3 years ago
Read 2 more answers
What will happen and give a reason
djyliett [7]

Answer:

1 or 2 or 3

Explanation:

it depends whether the coat is a light or dark colour. if it is lighly coloured it will not absorb heat from the sun and wont melt the snowman. if it is darkly coloured it will be number 1

the coat wont make a difference if the temperature of the snowman is the same and the temperature outside the snoman and the sun isnt shining. the coat would just make him look smart - so number 2

it coul keep in the cold and block out the warmth so number 3

4 0
4 years ago
Every surface has different ____________________ of friction.
dedylja [7]

Answer:

amounts

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every surface has different amounts of friction

hope this helps :) plz brainliest?

3 0
3 years ago
How does an inclined plane affect the effort needed to move a load vertically?
lys-0071 [83]

Answer:

Decreases

Explanation:

"Effort" usually refers to the applied force.  An inclined plane decreases the force required while increasing the distance that the force is exerted over.  So even though there's less force needed, the amount of work stays the same.

4 0
3 years ago
Eld a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 3.1
zheka24 [161]

Answer:

v_{f}=1721.1m/s

Explanation:

Given data

q = 3.1 µC

m = 47 mg

r1 = 0.83 mm

r2 = 2.5 mm.

As we know that:

dK=-dU\\(1/2)mv_{f}^{2}-(1/2)mv_{i}^{2}=-(\frac{kq^{2} }{r_{f}}-\frac{kq^{2} }{r_{i}} )\\    (1/2)*(47*10^{-6}kg )v_{f}^{2}-(1/2)*(47*10^{-6}kg)(0)=-[(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{2.5*10^{-3}}-(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{0.83*10^{-3}} )]\\2.35*10^{-5} v_{f}^{2}=69.61\\v_{f}=\sqrt{\frac{69.61}{2.35*10^{-5}} }\\v_{f}=1721.1m/s

5 0
3 years ago
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