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Pavel [41]
3 years ago
13

For each scenario below, choose the best graph. (a) Maria bikes from home to work.

Physics
1 answer:
BlackZzzverrR [31]3 years ago
5 0

A line graph that plots either speed or distance against time.

Really, the type of graph depends on what quantity you want the graph to show.

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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
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Well formation of metallic bond depends on free electrons.smaal sized atoms hold their electrons more firmly as compared to large size atoms ,this z due to distance of outer shell electrons by nucleus..in this way no of free electrons affect strength of metallic bond..smaal sized atoms release less free electrons..
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4 years ago
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In an equation f = l^2-d^2/4l the intercept is<br>​
DanielleElmas [232]

Answer:

the intercept is the orgin (0,0)

5 0
3 years ago
(06.02 MC)<br> What can a scientist use to observe very small things?
Naddika [18.5K]

Answer:

microscopic light or Nano technology

3 0
3 years ago
DetermiOne of the lines in the Balmer series of the hydrogen atom emission spectrum is at 397 nm. It results from a transition f
larisa86 [58]

Answer:

a)n =7 , b) n = 5

Explanation:

The energy levels of the hydrogen atom is described by the Bohr model

       E_{n} = - 13.606   1/n²

This equation energy is given in elector volts and n is an integer

A transition occurs when the electro sees from a superior to a lower state

       E₀ - E_{n} = -13.606 (1/n_{f}² - 1/n₀²)

Let's apply this expression

         n₀ = 2

Let's look for the energy of the different levels and subtract it

n₀          E_{n} (eV)

1            -13,606

2            -3.4015

3           - 1.5118

4           -0.850375

5           -0.54424

6           -0.3779

7           -0.2777

The wavelength of the transition is 397 nm = 397 10⁻⁹ m

The speed of light is related to wavelength and frequency

       c = λ f

The Planck equation gives the energy of a transition

      E = h f

      E = h c /λ

Let's calculate

     E = 6.63 10⁻³⁴ 3 10⁸/397 10⁻⁹

     E = 5.01 10⁻¹⁹ J

Let's reduce to eV

     E = 5.01 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

     E = 3.1313 eV

Let's examine the possible transitions from the initial level ni = 2

     ΔE = E_{2} - E_{n} = -3.1313

     En = 3.13 -3.4015

     E_{n} = 0.2702 eV

When examining the table we see that the level that this energy has is the level of n = 7

Part B      the transition is in the infrared

The frequency is 74 10¹² Hz

We use the Planck equation

       E = h f

       E = 6.63 10⁻³⁴ 74 10¹²

       E = 4.9062 10⁻²⁰ J

       E = 4.9062 10⁻²⁰ / 1.6 10⁻¹⁹

       E = 0.3066 eV

We look for the level with the energy difference

     ΔE = E₄- E_{n} = 0.3066

     E_{n} = 0.3066 - 0.85037

     E_{n} = -0.54376 eV

When examining the table this energy has the level n = 5, therefore from this level the transition occurs

6 0
4 years ago
In order to transmit information via radio waves, the waves need to be changed somehow. For car radios this can happen in two wa
laila [671]

Answer: amplitude

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Since we are considering AM which is amplitude modulation, a technique used in electronic communication, most commonly for broadcasting information through a radio carrier wave. In amplitude modulation, the amplitude (signal strength) of the carrier wave is diversified in proportion to that of the message signal being broadcasted.

7 0
4 years ago
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