6* 25 = 150 = (6*20= 120) + (6*5=30) Then Add 120+30= 150 so your answer is 5
Answer:
24 in
Step-by-step explanation:
Add up all the inches. voila!
First we should figure out how much over the weight limit the passengers are. We can find this by 750-450 which is 300. The amount of weight that needs to get off the elevator is 300 kilograms. Then, we know that each passenger weighs 70 kilograms. We can represent this as 70p.The inequality is 70p \geq 300. Then we can solve by dividing both sides of the inequality by 70. We get p \geq 4.28... Since people only come in whole numbers, and it has to be greater than 4.28, the number of excess passengers is 5.
Hope this helped!
Answer:
Test statistic = - 0.851063
- 2.520463
Step-by-step explanation:
H0 : μ ≥ 15
H1 : μ < 15
Sample mean, xbar = 14.5
Sample standard deviation, s = 4.7
Sample size = 64
Teat statistic :
(xbar - μ) ÷ (s/√(n))
(14.5 - 15) ÷ (4.7/√(64))
= - 0.851063
The critical value at α = 0.05
Using the T - distribution :
Degree of freedom, df = 64 - 1 = 63
Tcritical(0.05, 63) = 1.6694
Test statistic - critical value
-0.851063 - 1.6694
= - 2.520463
