Can someone help me with number 7 and 13 ? I graduate in a week an have to have this work done or I will not be graduating

alex spent 3/7 of his money he gave 1 /4 of the remainder to his sistet he haf $120 left how much money did he in the beginning

Sonbull [250]

Let his total money be x.
He spent (3/7)*x of his money.
He gave 1/4(x-3/7x) to his sister.
which is : (1/4)*(4/7)*x = (1/7)*x
Now,
How much money he have in the beginning =
(3/7)*x+(1/7)*x+120=x
(4/7)*x+120=x
120=x-(4/7)*x
120=(3/7)*x
x=120*7/3 [cross multiplication]
x=280.

So, Alex had $280 in the beginning.

6 0

3 years ago

Please answer with picture thank you so much!

Ilia_Sergeevich [38]

Answer: 28

Step-by-step explanation: In this problem, we're given information about the parts of a segment and we're asked to find the value of x.

To find the value of x, we can use the segment addition postulate.

Looking at the diagram, it should make since that RS + ST = RT.

So 4x + 3x + 11 = 60 or 7x + 11 = 60.

Subtracting 11 from both sides and solving for x, we get x = 7.

Since RS is 4x, we can substitute a 7 in for x to get 4(7) or 28.

8 0

3 years ago

A bicycle tire has a radius of 11 inches. To the nearest inch, how far does the tire travel when it makes 7 revolutions?

jok3333 [9.3K]

Answer:

d = 483.56 inches

Step-by-step explanation:

We have,

Radius of a bicycle tire is 11 inches. It is required to find the distance traveled by the distance covered by the tire when it makes 7 revolutions. One revolution means the circumference of circle. So,

$C=2\pi r\\\\C=2\times 3.14\times 11\\\\C=69.08\ \text{inches}$

In 7 revolution, it will cover a distance of 7C i.e.

$C=69.08\times 7\\\\C=483.56\ \text{inches}$

So, the tire will cover a distance of 483.56 inches in 7 revolutions

8 0

3 years ago

I need help on these question ASAP!!!! This is Urgent

GarryVolchara [31]

Part 1: The equation of the line is $y=2x+1$

Part 2: The equation of the line in slope intercept form is $y=-3x-1$

Explanation:

Part 1: It is given that the point A is $(1,3)$ and the line B is $y=2 x-2$

To determine the line passing through the point A and parallel to line B, let us first determine the slope and y-intercept.

From the equation of line B, the slope is $m=2$

Substituting the point $(1,3)$ and $m=2$ in slope intercept form $y=mx+b$ , we have,

$3=2(1)+b$

$3=2+b$

$1=b$

Thus, the y-intercept is $b=1$

Let us substitute the values $m=2$ and $b=1$ in the slope intercept form $y=mx+b$ , we get,

$y=2x+1$

Thus, the equation of the line passing though point A and parallel to line B is $y=2x+1$

Part 2: The given two coordinates are $(-1,2)$ and $(1,-4)$

To determine the equation of line in slope intercept form, first we shall find the slope and y-intercept.

From the graph, we can see that the line touches the y-axis at -1.

Hence, the y-intercept is $b=-1$

The formula for slope is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the coordinates $(-1,2)$ and $(1,-4)$ , we have,

$m=\frac{-4-2}{1+1} =\frac{-6}{2} =-3$

Thus, the slope is $m=-3$

Substituting the values $b=-1$ and $m=-3$ in the slope intercept formula $y=mx+b$ , we get,

$y=-3x-1$

Thus, the equation of the line in slope intercept form is $y=-3x-1$

4 0

3 years ago

What is the vertex of the graph y = x^2 + 6x - 5 ?

Dafna11 [192]

Given: y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.

The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.

Use the given formula y = x^2 + 6x - 5 to find the value of y when x = -3:

y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14

Then the vertex is (-3, -14).

6 0

3 years ago