You do the sum(40) subtracted by 8, the answer from that divided by 2 since Erin's two times younger.
40-8=32
32÷2=16
Then if you want to check it you do the opposite and get the same sum(40) so 16×2=32 and 32+8=40

6 0

3 years ago

What is the missing reason in the proof?Given: ∠ABC is a right angle, ∠DBC is a straight angleProve: ∠ABC ≅ ∠ABDdefinition of an

horsena [70]

For a better understanding of the solution provided here please find the relevant diagram drawn as per given information in the file attached.

As given, $\angle ABC=90^{\circ}$ . Also, it is given that $\angle DBC$ is a straight angle. Therefore, $\angle DBC=180^{\circ}$ .

As can be clearly seen from the diagram, if $\angle DBC=180^{\circ}$ and $\angle ABC=90^{\circ}$ , then:

$\angle ABD=\angle DBC-\angle ABC=180^{\circ}-90^{\circ}=90^{\circ}$

Therefore, $\angle ABD\cong\angle ABC$

Hence Proved.

7 0

3 years ago

What the answer ? someone pliss help me to do this

Nookie1986 [14]

Wow I lost brain cells trying to understand that. You need a Genius for that one

3 0

2 years ago