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3 years ago

Write an equation for the line that Is parallel to y=7x-13 and goes through the point (0, -9)

Mathematics

1 answer:

vekshin13 years ago

3 0

Answer:

the answer is y = 7x - 9

Step-by-step explanation:

hope this helps

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Billy went on the Yahoo Finance website to check the value of his investment. Yesterday his stock was worth

maxonik [38]

Answer:

The investment decreased by 16.5771% per share.

Step-by-step explanation:

7 0

3 years ago

What is the circumcenter of the points (2,6), (8,6), (8,10)

mario62 [17]

See https://web2.0calc.com/questions/need-help-now_10.

8 0

3 years ago

Following are heights, in inches, for a sample of college basketball players. 78 83 82 78 78 80 81 79 79 83 77 78 84 82 80 80 82

blagie [28]

The mean height of the basketball players is 80.3 inches

For given question,

we have been given the list of heights, in inches, for a sample of college basketball players.

We need to find the mean height of the basketball players.

We know that, for given sample of data

mean = sum of all observations ÷ total number of observation

First we find the sum of given heights.

78 + 83 + 82 + 78 + 78 + 80+ 81 +79+ 79 +83+ 77 +78+ 84+ 82+ 80+ 80 +82+ 84+78+ 80 = 1606

Total number of observations = 20

Using the formula of mean,

⇒ mean height = 1606/20

⇒ mean height = 80.3 inches

Therefore, the mean height of the basketball players is 80.3 inches

Learn more about the mean here:

brainly.com/question/6813742

#SPJ4

3 0

1 year ago

Select the correct answer.

DerKrebs [107]

I’m pretty sure the answer is c

8 0

3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

4 years ago