Ask question

Ask question

All categories

3 years ago

9

Which best describes the range of the function f(x) = 2(1/4) after it has been reflected over the y-axis? all real numbers all r

eal numbers less than 0 all real numbers greater than 0 all real numbers less than or equal to 0

2 answers:

trapecia [35]3 years ago

6 0

Answer:

All real numbers greater than 0.

Step-by-step explanation:

We have the function, $f(x) = 2(\frac{1}{4})^{x}$ .

'Reflection over y-axis means to flip the graph over y-axis', which changes the function by f(x) becomes f(-x).

So, after reflection, the given function transforms into,

$g(x)=f(-x)$

i.e. $g(x)=2(\frac{1}{4})^{-x}$

According to the graph of the function g(x), we see that,

Range of $g(x)=2(\frac{1}{4})^{-x}$ is the 'Set of all real non-negative numbers' i.e. {x | x > 0} i.e. $(0,\infty)$

juin [17]3 years ago

4 0

Your answer should be C
all numbers greater than 0

You might be interested in

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago

Line CD passes through points C(3,-5) and D(6,0). What is the equation of line CD in standard form?

Serga [27]

Answer:

hope this helps

the explanation is in the picture

please like and Mark as brainliest

3 0

2 years ago

2x+3=17 and x =7

mylen [45]

Answer:

The equation is true/ or an identity

Step-by-step explanation:

Plug in 7 for x, you get

2(7)+3=17

14+3=17

17=17

8 0

3 years ago

Read 2 more answers

If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le

Nikolay [14]

Answer:

$4\sqrt{\pi}$

Step-by-step explanation:

The cross section of a sphere is a circle with area $\pi r^2$ , where radius is given as 4
The cross section of the cube is a square with area $a^2$ , where a is side length of square

The circle area = the square area. Thus we have:

$\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}$

6 0

3 years ago

Read 2 more answers

Triangle DEF has vertices D(−4, 1), E(2, 3), and F(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of

CaHeK987 [17]

Answer: $D'(-14,1);\ E'(4,7);\ F'(4,1)$

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

$D_{O,k}(x,y)=(k(x-a)+a, k(y-b)+b)$

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

$(a,b)=(1,1)\\k=3$

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' → $(3(-4-1)+1,\ 3(1-1)+1)=(-14,1)$

Vertex E' → $(3(2-1)+1,\ 3(3-1)+1)=(4,7)$

Vertex F' → $(3(2-1)+1,\ 3(1-1)+1)=(4,1)$

6 0

3 years ago