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muminat
3 years ago
9

Which best describes the range of the function f(x) = 2(1/4) after it has been reflected over the y-axis? all real numbers all r

eal numbers less than 0 all real numbers greater than 0 all real numbers less than or equal to 0

Mathematics
2 answers:
trapecia [35]3 years ago
6 0

Answer:

All real numbers greater than 0.

Step-by-step explanation:

We have the function, f(x) = 2(\frac{1}{4})^{x}.

'Reflection over y-axis means to flip the graph over y-axis', which changes the function by f(x) becomes f(-x).

So, after reflection, the given function transforms into,

g(x)=f(-x)

i.e. g(x)=2(\frac{1}{4})^{-x}

According to the graph of the function g(x), we see that,

Range of g(x)=2(\frac{1}{4})^{-x} is the 'Set of all real non-negative numbers' i.e. {x | x > 0} i.e. (0,\infty)

juin [17]3 years ago
4 0
Your answer should be C 
all numbers greater than 0
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If 3x - 8= -2, find the value of x - 6.
siniylev [52]

Answer:

x-6 = -4

Step-by-step explanation:

3x - 8= -2

Add 8 to each side

3x - 8+8= -2+8

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Divide by 3

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What is the volume of a cylinder with a base radius of 2 and height of 6 ?
vodomira [7]

Answer:

V = 24pi

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Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We know the radius and the height

V = pi (2)^2 * 6

V = pi 4*6

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V = 3.14 * 24 = 75.36

If we use the pi button

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8 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!<br><br> Subract and simplify.
pantera1 [17]

Answer: C

<u>Step-by-step explanation:</u>

  \dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}

= \dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})

= \dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}

= \dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}

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5 0
3 years ago
5/8−(1/4)2= ________
bixtya [17]

Hey there!☺

Answer:\boxed{\frac{1}{8}}

Explanation:

\frac{5}{8}-(\frac{1}{4})2

Simplify:

\frac{5}{8}-\frac{1}{4}(2)=\frac{1}{8}

1/8 is your answer.

Hope this helps!☺

4 0
3 years ago
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