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3 years ago

At the beginning of the school year, there

Mathematics

2 answers:

melomori [17]3 years ago

7 0

Answer: 6% decrease

Step-by-step explanation:

Wewaii [24]3 years ago

5 0

Answer:

6% decrease

Step-by-step explanation:

Given that,

Initial number of students = 1200

At the end of the year there were 1128 students

We need to find the percent of change in enrollment.

Change in enrollment = 1200 - 1128 = 72

The percentage of change is :

$\%=\dfrac{\text{change in students}}{\text{initial students}}\times100\\\\\%=\dfrac{72}{1200}\times 100\\\\=6\%$

So, there is a decrease of 6% in number of students.

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The high school graduating class of 2010 was 260 people. Five years later the high school graduating class was 320 people. By ap

jeka94

Answer:

The high school graduating class changed by approximately 23%

Step-by-step explanation:

we have

The high school graduating class of 2010 was 260 people

Five years later the high school graduating class was 320 people.

we know that

260 people represent the 100%

The difference is (320-260)=60 people

using proportion

Find out what percentage represent 60 people

Let

x ----> the percentage that represent 60 people

$\frac{260}{100\%}=\frac{60}{x}\\\\x= 100\%(60)/260\\\\x=23.1\%$

therefore

The high school graduating class changed by approximately 23%

3 0

3 years ago

Which choice is the equation of a line that passes through the point (–6, –2) and is perpendicular to the line represented by th

kobusy [5.1K]

Answer:

B. y = 1/3x

Step-by-step explanation:

The slope of the given line is -3, so the slope of the perpendicular line will be the negative reciprocal of that: -1/(-3) = 1/3. This eliminates choices A and C.

We can find the y-intercept (b) if we use the given point values in the equation ...

y = 1/3x +b

we get ...

-2 = (1/3)(-6) +b

-2 = -2 +b . . . simplify

0 = b . . . . . . . add 2

So, the equation of the perpendicular line through the given point is ...

y = 1/3x . . . . matches choice B

_____

<em>Alternate solution method</em>

You can try the given point in the given equations. You will find that only the equation of choice B will work.

7 0

3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The

faltersainse [42]

Answer:

34%

Step-by-step explanation:

Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;

Mean , μ = 45 ; standard deviation, σ = 3

Using the empirical formula where ;

68% of the distribution is within 1 standard deviation from the mean ;

95% of the distribution is within 2 standard deviation from the mean

Lightbulb replacement numbering between ;

42 and 45

Number of standard deviations from the mean /

Z = (x - μ) / σ

(x - μ) / σ < Z < (x - μ) / σ

(42 - 45) / 3 = -1

This lies between - 1 standard deviation a d the mean :

Hence, the approximate percentage is : 68% / 2 = 34%

5 0

3 years ago

I need help with like terms

professor190 [17]

I’m guessing you mean like this.
2x+4y+5x+8y.
2x and 5x are like terms because the x’s are alike. If you add 2+5, the answer is 7. So therefore 2x+5x=7x.

4y and 8y are like terms because the y’s are alike. So the answer to 4y+8y would be 12y.

If you need extra help, give me a problem and I will help you solve it.

7 0

3 years ago

a. Write and simplify the integral that gives the arc length of the following curve on the given integral. b If necessary, use t

WINSTONCH [101]

Answer:

\int\limits^{\pi/2} _0 (1+4cos^{2} (2x)dx

Step-by-step explanation:

Arc length is calculated by dividing the arcs in to small segments ds

By pythagoren theorem

$ds^2=dx^2+dy^2$

then integrate ds to get arc length.

We are given a function as

y = sin 2x in the interval [0, pi/2]

To find arc length in the interval

Arc length $s =\int\limits^{\pi/2} _0 {1+y'^2} \, dx \\=\int\limits^{\pi/2} _0 (1+4cos^{2} (2x) )dx$

Hence arc length would be

B) $\int\limits^{\pi/2} _0 (1+4cos^{2} (2x)dx$

6 0

3 years ago