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3 years ago

Find the value of x. Round the length to the nearest tenth.

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

Answer:

Consider the given right triangle. We have to find the value of 'x'. So, the value of 'x' is 9.2 cm. Option 3 is the correct answer.

Step-by-step explanation:

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What is 41% of 53????

Law Incorporation [45]

Answer:

21.73

Step-by-step explanation:

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3 years ago

What is -9+n/4=-7? Please explain in detail, I don’t really understand this at all.

Brrunno [24]

Answer:

n=-19

Step-by-step explanation:

-9+n/4=-7

Multiply 4 on both sides

-9+n=-28

Add 9 on both sides

n=-19

5 0

3 years ago

What is 0.03 in scientific notation

aliina [53]

Answer: 3e-1

Step-by-step explanation: when it's going behind the decimal it will always be negative plus the reason it's one is because if you slide the decimal once it'll be the complete opposite

3 0

3 years ago

Find the solutions to the equation below 6x^2+5-4=0

Kipish [7]

Answer:i√6/6 , -i√6/6

Step-by-step explanation:

6x^2+5-4=0

6x^2=-5+4

x=√-1/6

x=±i√1/60=±i√1/√6*(√6/√6)=±i√6/6

3 0

3 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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3 years ago