Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
Step-by-step explanation:
Given that:
Population Mean = 7.1
sample size = 24
Sample mean = 7.3
Standard deviation = 1.0
Level of significance = 0.025
The null hypothesis:
The alternative hypothesis:
This test is right-tailed.
Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test 
The test statistics can be computed as:
t = 0.980
Decision rule:
Since the calculated value of t is lesser than, i.e t = 0.980 < , then we do not reject the null hypothesis.
Conclusion:
We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.
Let, the number = x
Then, 2(x + 10) = -20
2x + 20 = -20
2x = -20 - 20
x = -40/2
x = -20
In short, The number would be: -20
Hope this helps!
Answer:
Part A: Yes. For every 10 employees, an increase of 80 products produced.
Part B: y = 8x + 120
Part C: Y-intercept indicates the number of products produced when there are 0 employees. The slope indicates the rate of increase of production with the number of employees
Step-by-step explanation:
Part A: 80 - 0 = 80 employees; 760 - 120 = 640 products. Therefore, 640/80 = 8 products per employee <u>or</u> 80 products per 10 employees
Part B: For y = mx + c ,
m = (Y1 - Y0)/(X1 - X0) = (760 - 120)/(80 - 0) = 8
c = Y-intercept, when X = 0. Therefore c = 120
