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Svetach [21]
3 years ago
6

1) x-1+5

="absmiddle" class="latex-formula">+3=0
4) x^{4} -64=0
Mathematics
1 answer:
TEA [102]3 years ago
6 0

Answer:

See explanation below

Step-by-step explanation:

Find the value of x in each of the following

1) x-1+5√x-1+3=0

5√x-1 = -x -2

Square both sides

25(x-1) = (-x-2)^2

25(x-1) = x^2+4x + 4

25x-25 = x^2+4x + 4

x^2 +4x + 4 - 25x + 25 = 0

x^2 - 21x + 29 = 0

x = 21±√21²-4(29)/2

x = 21±√441-116/2

x = 21±√325/2

x = 21±18.03/2

x = 21+18.03/2 and 21-18.03/2

x = 19.515 and 1.485

4)  x^4-64=0

x^4 = 64

x = \sqrt[4]{64}

x = 2.83

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<u>Proportional Geometric Shapes </u>

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