Answer:
length = 18yd
Width = 10yd
Step-by-step explanation:
Complete question
<em>A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 180 square yards. Find the length and the width.</em>
Area of the parking lot - length * width
A = LW
Given
Area = 180sq. yd
If the parking lot has a length that is 8 yards greater than the width, then;
L = 8 + W
The area becomes;
A = (8+W)W
180 = 8W+W²
W²+8W - 180 = 0
W²+18W-10W - 180 = 0
W(W+18)-10(W+18) = 0
(W-10)(W+18) = 0
W-10 = 0
W = 10yd
Since L = 8 + W
L = 8 + 10
L = 18yd
Hence the length and the width area 18yd and 10yd respectively
$276 in 12 hours hopes this help 23x12=276
C
1. Substitute the 8 for g
2. Divide it by 2
3.Then add by 3
The solution of given equation is: -9
Step-by-step explanation:
Given equation is:
4x = -36
In order to solve these type of equations, we have to isolate the variable on one side of the equation
So in order to solve this equation, we have to divide both sides by 4
Hence,
The solution of given equation is: -9
Keywords: Linear equation, variables
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Answer:
B, 118°
Step-by-step explanation:
The sum of angles on a straight line is 180° (because the measure of a straight line is 180°)
Thus:
m∠RSU + m∠UST = 180°
Substitute m∠UST with 62°.
m∠RSU + 62° = 180°
Subtract both sides by 62°.
m∠RSU = 118°
So, the answer is B, 118°
I hope this helps! Feel free to ask any questions!