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Is 2 a solution to the equation 1/2x-4=5?

dusya [7]

9514 1404 393

Answer:

no

Step-by-step explanation:

Put 2 where x is and see if you get a true statement.

1/2(2) -4 = 5

1 -4 = 5

-3 = 5 . . . . . . False

2 is not a solution to the equation.

__

The solution is x=18.

6 0

2 years ago

How many home runs did each player hit the season

olya-2409 [2.1K]

Let Peter's hit be x and Alice's runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)

Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8

Therefore, Peter hit 8 home runs and Alice hit 10 home runs.

3 0

3 years ago

Free poitnssssssssssssssssssssssssssssssss

puteri [66]

Thank you kind sir

The purpose of life is to learn and pass on what you have learned. We all started out a cell. That cell then became two. All throughout time people have learned and passed on their knowledge. There is no real purpose to life except to learn and then pass on. From birth to death we learn and pass it on and in years, later on, we will know more and more. Never stopping this cycle. Until we know too much and the world ends from the power and fighting of the powers of human exists.

4 0

2 years ago

Read 2 more answers

last year, Nicole biked n miles. This year, she biked 524 miles. Using n, write an expression for the total number of miles she

Fittoniya [83]

Answer:

n+524

Step-by-step explanation:

you add both years worth of biking together!

7 0

2 years ago

A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d

bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

$\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}$

For this case, we're given that:

Sample size n = 90 > 30
Sample mean = $\overline{x}$ = 138
Sample standard deviation = s = 34
Level of significance = $\alpha$ = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: $Z_{0.1/2}$ = ±1.645

Thus, we get:

$CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]$

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0

2 years ago