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zmey [24]
3 years ago
9

~Hi ~ Hi ~ Can ~ you ~ please ~ help ~ me ~ out? ~

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0

Answer:

d

Step-by-step explanation:

borishaifa [10]3 years ago
6 0

Answer:200.96

Step-by-step explanation:

16 divided by 2= 8

3.14 x 8 x 8

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Jessie colored poster .She colored 2/5 of the poster red .Write a fraction that is equivalent to 2/5.
Inessa [10]
4/10 is equivalent to 2/5. Thx!
8 0
3 years ago
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Lucia has 3.5 hours left in her workday as a car mechanic. Lucia needs 1/2 of an hour to complete one oil change.
MatroZZZ [7]

Answer: So Lucía has 3.5 hours left, and need 1/2 of an hour (or 0.5 hours) to do one oil change.

a) If you divide the total time she has by the time she needs for each oil change, then you got the total number of oil changes that she can do in that time; this is:

3.5/0.5 = 7

So she can do 7 oil changes in 3.5 hours.

b) If she can complete two car inspections in the same amount of time it takes her to complete one oil change, then she can do two car inspections in 0.5 hours.

2*car inspections = 0.5 hours

car inspection = (0.5/2) hours

then one car inspection will take 0.5/2 = 0.25 hours.

c) Two ways to solve this:

1) Do the same that we did in a), this is: 3.5/0.25 = 14

she can do 14 car inspections.

2) If in 3.5 hours, she can do 7 oil changes, and in the time she does an oil change, she can do two car inspections, then in 3.5 hours she can do 7*2 car inspections, and 7*2 = 14

5 0
3 years ago
Read 2 more answers
Help please thanks!!!
Andreyy89
You already have the right Answer which is b
6 0
3 years ago
Read 2 more answers
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
15+21= in distributive property to factor out the greatest common factor
ASHA 777 [7]

Answer:

So the greatest common factor 15 and 21 is 3.

Step-by-step explanation:

5 0
3 years ago
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