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Usimov [2.4K]
3 years ago
7

Which method would prove the quadrilateral is a parallelogram?

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

Answer: Each pair of opposite sides has the same measure. Therefore, they are congruent. If both pairs of opposite sides of a quadrilateral are congruent, the quadrilateral is a parallelogram.



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A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
mamaluj [8]

Answer:

Systolic variation coefficient (CVS) = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) =  0.1789 = 17.89%

The variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

Step-by-step explanation:

Systolic Mean (MS) = 127.8

Diastolic Mean (MD) = 73.5

Standard Deviation Systolic (sdS) = 18,486

Standard Deviation Diastolic (sdD) = 13.1508

The coefficient of variation is defined by:

Systolic variation coefficient (CVS) = sdS / MS = 18.486 / 127.8 = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) = sdD / MD = 13.1508 / 73.5 = 0.1789 = 17.89%

Then, it can be concluded that the variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

8 0
3 years ago
The cost of 10 ice creams at an ice cream stand is $20. Which graph shows the cost of different numbers of ice cream at the ice
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Every 1 ice cream is 1/2 dollar
7 0
3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

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3 years ago
Linear or nonlinear!?
NeTakaya

Answer:

nonlinear

Step-by-step explanation:

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creativ13 [48]

Answer:

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3 years ago
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